If I'm saving an object to a stream, how do I know how many bytes a variable of an enumerated type takes? There are 7 possible values in the one I'm looking at. I can't find this information in the helpfile. (I can't find practically any information in the D2007 helpfile, for that matter. Who wrote this thing?!?)
Anyone know an authoritative answer?
Mason
I won't call mine authoritative, but I know something of this.
Enumerated types are really just integer fields with defined constants associated in name and in incremental value. If you use them as just an enumerated type they should default to 1 byte in size, unless you have more than 255 elements. In a set, however, each element represents a bit toggle ... and so you need to divide your elements by 8 and round up (minimum of 1).
Thus an enumerated type of 16 elements is 1 byte in size, but a set of that type is 2 bytes in size.
Hope that helps.
http://www.delphibasics.co.uk/RTL.asp?Name=$MinEnumSize
From brazil (:
Pascal pownz!
Worth to note is that the default value of the minenumflag in freepascal isnt 1 as in delphi, wich has caused me some headace.
/Andreas
Oh, and this code appears to be an approximate replacement for return(random()&0x01);
http://www.pascalgamedevelopment.com/viewforum.php?f=71
http://www.phoenixlib.net/
Frankly, I never assume the size of anything when playing with memory or streams, but always use sizeof(TMyEnum) for safety. This way it would work between compilers, as each would report the size and you wouldn't actually have to know.
I'm not the guru, but I can say that I've done something like that. You simply do:
[pascal]
var
S: TStream;
X: TSimpleEnum;
begin
S.Write(X, SizeOf(TSimpleEnum));
end;
[/pascal]
That's all you need, it worked for me.
Oh, so you can set the value with $minenumsize ? That's great! Thanks.
It is 1 in Delphi mode.Originally Posted by Andreaz
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